7(t^2+5t-9)+t=t(7t-2)+3

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Solution for 7(t^2+5t-9)+t=t(7t-2)+3 equation: 



7(t^2+5t-9)+t=t(7t-2)+3

We move all terms to the left:

7(t^2+5t-9)+t-(t(7t-2)+3)=0

We add all the numbers together, and all the variables

t+7(t^2+5t-9)-(t(7t-2)+3)=0

We multiply parentheses

7t^2+t+35t-(t(7t-2)+3)-63=0



We calculate terms in parentheses: -(t(7t-2)+3), so:

t(7t-2)+3

We multiply parentheses

7t^2-2t+3

Back to the equation:

-(7t^2-2t+3)



We add all the numbers together, and all the variables

7t^2+36t-(7t^2-2t+3)-63=0

We get rid of parentheses

7t^2-7t^2+36t+2t-3-63=0

We add all the numbers together, and all the variables

38t-66=0

We move all terms containing t to the left, all other terms to the right

38t=66

t=66/38

t=1+14/19

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